The gas inside a large engine cylinder initially has a pressure of 105 kilopascals and a volume of 2.031 liters. if the gas is compressed at constant temperature to a volume of 0.356 liter, what is its new pressure? the pressure of the compressed gas kilopascals. just fill in the blank u

The  new  pressure  of the compressed  gas is 599 kilopascals

    calculation

This is calculate using  Boyle's  law  formula

That is P₁V₁ =P₂V₂

where;

P₁ = 105 kilopascals

V₁ = 2.031 L

P₂ = ?  kilopascals

V₂ =0.356 L

make P₂ the subject of the formula  by diving both side of equation by V₂

P₂ = P₁V₁/V₂

P₂ = {(105 kilopascals  x 2.031 L)/0.356 L} = 599 kilopascals

599 Kp

Explanation:

- lead + phosphoric acid = hydrogen + lead(ii) phosphate

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