Given the balanced equation below, calculate the moles of aluminum that are needed to react completely with 17.5 moles of feo? show all work 2al+3feo—> 3fe+al2o3

The  moles  of Al that are needed to react completely  with 17 .5  moles  of FeO  is  11.67  moles

calculation

2Al +3 FeO  → 3 Fe + Al₂O₃

The moles of Al  is calculate using the mole ratio

That is; From equation above the  mole  ratio  of Al :FeO is 2:3  therefore the moles of Al

  = 17.5 moles x 2/3 = 11.67  moles

the only liquid elements at standard temperature and pressure are bromine (br) and mercury (hg). although, elements caesium (cs), rubidium (rb), francium (fr) and gallium (ga) become liquid at or just above room temperature.

explanation: