What did i do wrong? ? solid sodium reacts violently with water, producing heat, hydrogen gas, and sodium hydroxide. how many molecules of hydrogen gas are formed when 48.7 g of sodium are added to water? show your work. (4 points)2na + 2h2o > 2naoh + h22na + 2h2o > 2naoh + h248.7 g ? molecules2 mol na= 1 mol h21 mol na= 23g na1 mol h2= 6.02x1023 molecules (48.7g na/1)x(1 mol na/23g na)x(1 mol h2/2mol na)x(6.02x1023/1 mol h2) (48.7)(6.02x1023)/(23)(2)= 293.174x1023 molecules can someone tell me what i did wrong?

The molecules  of hydrogen gas that are  formed is  when 48.7 g  of sodium are added to water  is  6.375  x 10²³  molecules

  calculation

2 Na +2H₂O →  2 NaOH  +H₂

Step 1: find the moles  of sodium (Na)

moles =mass÷   molar mass

from periodic table the molar mass of Na = 23 g/mol

moles= 48.7 g÷ 23 g/mol =2.117 moles

Step 2:use the mole ratio to determine  the  moles of H₂

  from  given equation  Na:H₂ is 2:1

therefore the moles  of H₂ = 2.117 moles x 1/2=1.059 moles

Step 3: find the molecules of H₂ using the Avogadro's law

According  to  Avogadro's  law  1 mole = 6.02 x 10²³ molecules

                                                      1.059 moles = ?  molecules

by cross multiplication

= [(1.059 moles x 6.02 x10²³  molecules) /  1 mole] =6.375  x 10²³  molecules

the product of the pressure and volume is also constant