Calculate the kinetic energy, in j/mole, of 1.00 mole of gaseous water molecules at room temperature (25.0ºc).

23158.7J/mol

Explanation: Kinetic energy is the energy possessed by a body by virtue of its motion.

R= gas constant= 8.314 J/Kmol

T= temperature in Kelvin = 25 ° C = 25° C+273= 298 K

K.E = 23158.7 J

n= no of moles = 1 mole

Thu K.E per mole will be= 23158.7 J/mol

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they are both synthetic elements

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