If 0.500l solution weighs 596g and contains 90.0g of oxalis acid, the concentration can be expressed as ? m, or ? (m/m)%, or ? (m/v)%.

Answer : The concentration can be expressed as, 1.99 M, or 15.1(m/m)%, or 18(m/v)%

Solution : Given,

Volume of solution = 0.5 L = 500 ml        (1 L = 1000 ml)

Mass of solution = 596 g

Mass of oxalic acid, (solute) = 90 g

Molar mass of oxalic acid = 90.03 g/mole

First we have to calculate the concentration in terms of M(molarity).

Molarity : Molarity is defined as the number of moles of solute present in one liter of solution.

Formula used :

where,

M = molarity of solution

= mass of solute(oxalic acid)

= molar mass of solute(oxalic acid)

= volume of solution(in liters)

Now put all the given values in this formula, we get

Now we have to calculate the concentration in terms of (m/m)%

(m/m)% : It is defined as the mass of solute present in mass of solution in grams.

Formula used :

where,

= mass of solution

Now we have to calculate the concentration in terms of (m/v)%

(m/v)% : It is defined as the mass of solute present in one milliliter of solution.

Formula used :

where,

= mass of solution

1.43 x 10^-11 j the guy commented the awnser just making sure u see it .

atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8