Chemistry, 27.06.2019 20:30 help1572

John has to hit a bottle with a ball to win a prize. he throws a 0.4 kg ball with a velocity of 18 m/s. it hits a 0.2 kg bottle, and the bottle flies forward at 25 m/s. how fast is the ball traveling after hitting the bottle?

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One can solve the problem by using the law of conservation of momentum. The total momentum prior to the collision must be equivalent to the total momentum after the collision, so we have:

m1v1 + m2v2 = m1v1 + m2v2

Here, m1 is 0.4 Kg that is the mass of the ball, u1 is 18 m/s that is the initial velocity of the ball, m2 is 0.2 Kg that is the mass of the bottle, and u2 is 0 that is the initial velocity of the bottle.

v1 is the final velocity of the ball, which is to be determined, and v2 is 25 m/s that is the final velocity of the bottle.

Substituting and rearranging the equation, one can find the final velocity of the ball:

v1 = m1u1 - m2v2 / m1 = (0.4 kg) (18 m/s) - (0.2 Kg) (25 m/s) / 0.4 Kg = 5.5 m/s.

Answer from: elsauceomotho

Explanation:

The given data is as follows.

$m_{1}$ = 0.4 kg, $u_{1}$ = 18 m/s

$u_{2}$ = 0 m/s, $v_{2}$ = 25 m/s

$m_{2}$ = 0.2 kg, $v_{2}$ = ?

As we know that, according to the law of conservation of momentum

$m_{1}u_{1} + m_{2}u_{2}$ = $m_{1}v_{1} + m_{2}V_{2}$

Hence, putting the given values into the above formula as follows.

$m_{1}u_{1} + m_{2}u_{2}$ = $m_{1}v_{1} + m_{2}V_{2}$

$0.4 kg \times 18 m/s + 0.2 \times 0 m/s$ = $0.4 \times v_{1} + 0.2 \times 25 m/s$

7.2 = $0.4v_{3} + 5.0$

$v_{3}$ = 5.5 m/s

Thus, we can conclude that the ball traveling at a speed of 5.5 m/s after hitting the bottle.

Answer from: Quest

The activity series is shown in the attached picture. if the element is below the other, then you can displace the other. following the activity series as a guide, the reactions are as follows: nickel and aluminum chloride3 ni + 2 alcl₃ → 3 nicl₂ + 2 albarium and copper bromideba + cubr → no reaction because cu is less oxidizable than bapotassium nitrate and aluminum3 kno₃ + al → al(no₃)₃ + 3 ksodium phosphate and zincnaso₄ + zn → znso₄ + na

Answer from: Quest

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.

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John has to hit a bottle with a ball to win a prize. he throws a 0.4 kg ball with a velocity of 18 m...

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