What is the molarity of 60 grams of naoh dissolved in 750

Here we need to find the morality of 60 grams of NaOH dissolved in 750ml because the amount of solute is usually taken in ml and 750 litres is way to high.

So, coming towards the question, we need to find molarity.

As we know, molarity is no of moles of a substance per litre of the solution.

                                           Molarity= mole\volume > 1

Now we will change 750ml  to litres

                                      750/1000 = 0.75 litres

Now we need to find no of moles of NaOH.

As we know, no of moles = mass /molar mass

                       no of moles =60 grams / 40

                       no of moles= 1.5 moles

Putting the values of no of moles and volume in equation 1

                               Molarity= mole\volume > 1

                                             =1.5 moles/ 0.75 litres

                                             =2 M

So the answer will be 2 Molar.

if the concentration of products is decreased, the equilibrium will shift toward the products). add an inert gas (one that is not involved in the reaction) to the constant-volume reaction mixture: this will increase the total pressure of the system, but will have no effect on the equilibrium condition.

explanation:

particle   p is an electron and particle q is a neutron