For the equation 4al + 3o2 → 2al2o3, how many grams of aluminum oxide can be produced from 54 grams of aluminum?

Answers:  

1.02 g

Explanation:  

We know we will need a balanced equation with masses and molar masses, so let’s gather all the information in one place.  

M_r:       26.98              101.95  

               4Al + 3O₂ ⟶ 2Al₂O₃

Mass/g:   54  

1. Calculate the moles of Al  

Moles Al = 54 × 1/26.98  

Moles Al = 2.00 mol Al  

2. Calculate the moles of Al₂O₃  

The molar ratio is 2 mol Al₂O₃:4 mol Al  

Moles of Al₂O₃ = 2.00 × 2/4  

Moles of Al₂O₃ = 1.00 mol Al₂O₃

3. Calculate the mass of Al₂O₃  

Mass of Al₂O₃  = 1.00 × 101.95

Mass of Al₂O₃  = 1.02 g

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