How much heat can be obtained from the condensation of 36.2 g of methanol vapor (mm = 32.04 g/mol) at its boiling point to 36.2 g of liquid methanol at the same temperature? â†hvap = 35.2 kj/mol cliquid = 2.533 j/gâ—¦c cgas = 44.06 j/gâ—¦c

q = -39.8 kJ

Step-by-step explanation:

CH₃OH(g) ⇌ CH₃OH(l); ΔH(cond) = -35.2 kJ·mol⁻¹

(1) Calculate the moles of methanol

n = 36.2 × 1/32.04

n = 1.130 mol

(2) Calculate the heat evolved

q = nΔH(cond)

q = 1.130 × (-35.2)

q = -39.8 kJ

answer: c. the experiment shows that the red substance experienced a chemical change.

explanation: chemical change is the change in which chemical composition of the substance changes. physical change is the change in which there is no change in chemical composition.

chemical changes are accompanied by following changes:

a) precipitate formation

b) energy is released or absorbed

c) formation of bubbles

d) change in color

as it is given that the red color has disappeared and there is production of gas, it means the red substance has undergone a chemical change.

e