A20 l cylinder of gas at 5.6 atm pressure at 35 degrees celsius is heated to 95 degree celsius and compared to 23 atm. what is the new volume?

5.8 L  

Step-by-step explanation:

This looks like a case where we can use the Combined Gas Law to calculate the temperature.

p₁V₁/T₁ = p₂V₂/T₂               Multiply both sides by T₂

p₁V₁T₂/T₁ = p₂V₂                Divide each side by V₂

V₂ = V₁ × p₁/p₂ × T₂/T₁  

Data:

p₁ = 5.6 atm

V₁ = 20 L

T₁ = 35 °C = 308.15 K

p₂ = 23 atm

V₂ = ?

T₂ = 95 °C = 368.15 K

Calculation:

V₂ = 20 × 5.6/23 × 368.15/308.15  

V₂ = 20 × 0.243 × 1.19  

V₂ = 5.8 L  

i look it up online and i'll tell you

the answer is the first option

explanation:

just googled it m8. not that hard

lol