What volume of nitrogen dioxide is produced from the complete reaction of 16.87g of lead at stp? 2pb(> 2pbo(s)+4no2(g)+o2(g)

16.78 g of lead(II) nitrate will produce 2.238 L of NO2

Explanation:

n(lead nitrate) = 16.87/331.2 = 0.05 mole

0.05 mole of lead nitrate will produce 0.1 mole of nitrogen dioxide (NO2)

at STP: P = 1.0 atm and T = 273.0 K

R = 0.082 L.atm/mol.K

V = nRT/P

V = (0.10 mol)(0.082 L.atm/mol.K)(273.0 K)/(1.0 atm) = 2.238 L

answer: semi-infinite solid initially at a uniform temperature of 400 ◦c is cooled at its surface by convection. the cooling fluid at a constant temperature of 200 ◦c has a convective coefficient (ha) of 250 w/m2.k. the physical properties of the solid: k = 20 w/m.k and α = 4 * 10-5  m2/s. using δx = 0.04 m and δt = 10 s. write the finite difference equations describing the transient heat transfer of the first five δx and the temperature profile after 30 s.