Hydrogen and nitrogen react to form ammonia according to the reaction, 3 h2 + n2 2 nh3 if 4.0 moles of h2 with 2.0 mol of n2 are reacted, how many moles of nh3 would be produced? 0.38 mol 2.0 mol 4.0 mol 2.7 mol

2.7 mol

Explanation:

we have the following reaction

Data

First we must calculate what the limit reagent is.

the limit reagent is consumed first, when it is consumed completely the reaction is finished

This means that in order to fully consume 4 moles of hydrogen, 1.3 moles of nitrogen are needed, since we have more than this amount of nitrogen (the nitrogen is in excess) is our excess reagent and hydrogen is our limit reagent. so much is it that determines how much product is formed

From the stoichiometric coefficients of the reaction we know that three moles of hydrogen are needed to produce two moles of ammonia

So how many moles of ammonia will be produced if we have 4 moles of hydrogen

To solve it we apply a simple rule of three

2.7 mol NH_3 are produced

i dont know

explanation:

50.23 i believe is correct but don't quote me on that.