Select the correct answer. if the emf produced in a wire is 0.88 volts and the wire moves perpendicular to a magnetic field of strength 0.075 newtons/amp·meter at a speed of 4.20 meters/second, what is the length of the wire in the magnetic field?

Given:

EMF = 0.88 V

Strength of magnetic field, B = 0.075 N/A-m

Velocity, v = 4.20 m/s

To determine:

The length of wire, L

Explanation:

The EMF is related to strength of the magnetic field B as:

EMF = L*B*v

L = EMF/B*v = 0.88/0.075*4.20 = 2.79 m

Ans: The length of the wire is around 2.8 m

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