Given the following equation: 4al + 3o2 → 2al2o3. how many grams of aluminum oxide would form from reaction if 12.5 moles of aluminum burned?

6.25 moles Al2O3

Since all provided numbers are moles, there is no need for conversion. Rather, use a molar ratio:

12.5

Multiply across the top, 12.5 x 2, which gives you 25, before dividing that by the denominator (4).

This gives you the final answer of 6.25 moles of Al2O3.

Hope this helps!

for points guys