Agas at constant volume has a pressure of 2.80 atm at 400. k. what will be the pressure of the gas at 360. k? 2.52 atm 2.94 atm 3.11 atm 3.78 atm

Hello!

A gas at constant volume has a pressure of 2.80 atm at 400. K. What will be the pressure of the gas at 360. K?

We have the following information:

P1 (initial pressure) = 2.80 atm

T1 (initial temperature) = 400 K

P2 (final pressure) = ? (in atm)

T2 (final temperature) = 360 K

According to the Law of Charles and Gay-Lussac in the study of gases, we have an isochoric (or isovolumetric) transformation when its volume remains constant or equal, if the temperature increases, the pressure increases and, if the temperature decreases, the pressure also decreases, they are directly proportional.then we will have the following formula:

multiply the means by the extremes

2.52 atm

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I Hope this helps, greetings ... Dexteright02! =)

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.