It takes moles of oxygen to burn 32.0 g of methane. ch4 + 2o2 → co2 + 2h2o a. 1 mol b. 4 mol c. 3 mol d. 2 mol

the balanced equation for the combustion reaction is

CH₄ + 2O₂ ---> CO₂ + 2H₂O

molar ratio of methane - CH₄ to O₂ is 1:2

mass of methane burned - 32.0 g

number of methane moles burned - 32.0 g / 16 g/mol = 2 mol

according to molar ratio 1 mol of methane reacts with 2 mol of oxygen

therefore 2 mol of methane reacts with 4 mol of oxygen

answer is B. 4 mol

it should be all of them because it asks if you included all of those in your answer

explanation: