Ethylene glycol [ch(oh)ch2(oh)] is a common automobile antifreeze. calculate the freezing point and boiling point of a solution containing 273 g of ethylene glycol and 1055 g of water.

Ethylene glycol (EG), CH2(OH)CH2(OH), is a common automobile antifreeze. It is water soluble and fairly volatile (b.p. 197°C). Calculate the boiling point and freezing point of a  

solution containing 373.5 g of ethylene glycol in 3099 g water. The molar mass of  

ethvlene glvcol is 62.07 s/mol.  

Equation:

(373.5 g C2H6O2) / (62.07 g/mol C2H6O2) / (3099 g H2O) x (1000 g H2O) = 1.9417 m  

(1.9417 m) x (1.86 °C/m) = 3.61 °C change  

0°C - 3.61 °C = -3.61 °C  

(1.9417 m) x (0.512 °C/m) = 0.994 °C change  

100°C + 0.994 °C = 100.99 °C

This is the equation if you were to do it with different numbers.

where are the choice options?