Molecules of sugar are attracted to each other and form crystals. if you place sugar in water, the crystals break apart, but the molecules remain the same kind of sugar. what can you infer about the bonds between atoms in a sugar molecule compared with the forces that attract sugar molecules to each other?

Explanation:

So here's the thing . Sugar molecule is a molecular solid . It a relatively weak molecule

We all know the formula of glucose ( which is a sugar type molecule ) which is C12 H22 O 11 . This is basically bonded together by dipole dipole forces ( remember that this force of attraction is weak ) .on the other hand you have the solution ( which is usually water) .water is held by strong attraction forces known as hydrogen bonding .since this type of bonding is greater than dipole dipole forces .therefore when glucose is dropped in water . water is easily able to obercome the forces that are keeping the glucose molecule intact . therefore the molecule dissolves and breaks into pieces. Hope this helps

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.