If 125 cal of heat is applied to a 60.0-g piece of copper at 25.0 ? c , what will the final temperature be? the specific heat of copper is 0.0920 cal/(g? ? c) .

Amount of heat = mass x specific heat x change in temperature

125 = 60.0 x 0.0920 x Dt

So Dt = 125 / 5.52

= 22.65

Final temperature = 24 + 22.65 = 46.65 degree C

hope that help

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the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.