What would happen to a weak base dissociation equilibrium if more products we added

The position of equilibrium will shift to the left.

Step-by-step explanation:

The general equation for the dissociation of a weak base is

B + H₂O   ⇌   BH⁺ + OH⁻

According to Le Châtelier's Principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

If you apply a stress by adding more BH⁺ or OH⁻,  the system will respond by moving in a direction that gets rid of the added ions.

The position of equilibrium will shift to the left, forming more of the undissociated base.

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.