Nitrogen dioxide decomposes according to the reaction 2 no2(g) ⇌ 2 no(g) + o2(g) where kp = 4.48 × 10−13 at a certain temperature. if 0.70 atm of no2 is added to a container and allowed to come to equilibrium, what are the equilibrium partial pressures of no(g) and o2(g)

Partial pressure of the oxygen gas at equilibrium:

Partial pressure of nitrogen monoxide gas at equilibrium:

Explanation;

Initial Partial pressure of nitrogen dioxide gas = p = 0.70 atm

The value of for the reaction

Initially     p

At eq'm  p-2x          2x   x

On solving for the x

Partial pressure of the oxygen gas at equilibrium:

Partial pressure of nitrogen monoxide gas at equilibrium:

its going to be mutualism cuz they both benefit from the relationship.

~batmans wife dun dun

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