Chemistry, 22.06.2019 12:00 leo4687

What is a possible quantum number set for an electron in the 3s orbital of a magnesium atom

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Answer from: taykola

n = 3l = 0 m_l

= 0

= 1/2 or -1/2Explanation

There are four quantum numbers in an electron that orbits the atom.

n, the principal quantum number.l, the angular quantum number. m_l

, the magnetic quantum number. m_s

, the spin quantum number.

n is a positive integer. The value of n indicates the main shell of the electron. The electron in question is in the 3s orbital. As a result, n = 3.

l is a non-negative integer. The value of l indicates the type of subshell ("orbital") of the electron. The types of subshells possible depends on the main shell. For example, both s and p orbitals exist in the second main shell. However, only the s orbital exists in the first main shell. The value of l ranges from 0 to n - 1.

l = 0 indicates an s orbital.l = 1 indicates a p orbital.l = 2 indicates a d orbital.l = 3 indicates an f orbital.

The electron in question is in an s orbital. As a result, l = 0.

m_l is an integer. The value of m_l indicates the position of the electron within the subshell. The range of m_l depends on the value of l. m_l ranges from -l to l (that's -l, ..., -1, 0, 1, ... l). Accordingly, there are 2 l + 1 orbitals in a l subshell. l = 0 for this 3s electron. There's only one orbital in the 3s subshell. The only m_l value possible for this electron is 0.

The value of m_s is either - 1/2 or 1/2. It indicates the position of an electron within a single orbital. The value of m_s does not depend on that of n, l, or m_l . However, by the Pauli Exclusion Principle, at least one of the four numbers must differ for two electrons in the same atom. In case all three of n, l, and m_l are the same, the two electrons must differ in m_s . However, this question asks only for the number of one single electron. Thus, giving either - 1/2 or 1/2 shall work.

Reference

Vitz et. al, "5.8 Quantum Numbers (Electronic)", ChemPRIME (Moore et al.), Chemistry Libretexts. 27 Oct 2017.

Answer from: Quest

The correct answer is c. orbital shape. "the angular momentum quantum number l describes the shape of an orbital. it corresponds to each orbital type, i.e. (0,1,2,−1)=(s,p,d,f,g,"

Answer from: Quest

ca has a crystalline lattice with positive ions (since it is a metal, metals are positively charged) and electrons flow freely in its structure since the ca atoms have a large nuclear radius so the electrons are not tightly held, therefore the electrons can flow freely since they are not being highly attracted by the nucleus. moreover, one of the properties of metals are that they are conductors of electricity, thus proving ca is the element.

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What is a possible quantum number set for an electron in the 3s orbital of a magnesium atom...

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