Find the mass in grams of hydrogen gas produced when 14.0 moles of hcl is added to an excess amount of magnesium.

14.0 g of hydrogen gas

The equation for the reaction is

Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)  

From the equation, 2mol HCl will produce 1 mol H2

Moles of HCl =14 moles

Therefore; 14 moles of HCl will produce 7 moles of hydrogen gas

1 mole of Hydrogen gas = 2.0 g/mol

Thus; mass of 7.0 moles of H2 = 7 × 2.0 g/mol

                                                   = 14.0 g

the answer is c. nacl

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