Chemistry, 18.01.2020 06:31 webbjalia04

In the following balanced equation 2c2h6 + 7o2 --> 4co2 + 6h20 if 7.0 g of c2h6 react with 18g of o2, how many grams of water will be produced?

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Answer from: bee3176

Amount of water produced is 8.6778 grams.

Explanation:

To calculate the amount of water produced, we first need to find the limiting reagent and for it we need to find the number of moles. To calculate the moles, we use the following equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ...(1)

Moles of

Given mass of C_2H_6 = 7 grams

Molar mass of C_2H_6 = 30 g/mol

Putting values in above equation, we get:

$\text{Number of moles}=\frac{7g}{30g/mol}=0.2333moles$

Moles of

Given mass of O_2 = 18 grams

Molar mass of O_2 = 32 g/mol

Putting values in above equation, we get:

$\text{Number of moles}=\frac{18g}{32g/mol}=0.5625moles$

For the given chemical reaction, the equation follows:

$2C_2H_6+7O_2\rightarrow 4CO_2+6H_2O$

By Stoichiometry:

7 moles of oxygen reacts with 2 moles of ethane.

So, 0.0261 moles of lead nitrate are produced by = $\frac{2}{7}\times 0.5625=0.1607moles$ of ethane.

As, the required amount of ethane is less than the given amount. Hence, it is considered as the excess reagent.

Oxygen gas is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

7 moles of oxygen gas produces 6 moles of water.

So, 0.5625 moles of oxygen gas will produce = $\frac{6}{7}\times 0.5625=0.4821moles$ of water.

Now, to calculate the mass of water produced, we use equation 1.

Molar mass of water = 18 g/mol

Moles of water produced = 0.4821 moles

Putting values in the equation, we get:

$0.4821mol=\frac{\text{Mass of water}}{18g/mol}$

Mass of water produced = 8.6778 grams.

Hence, amount of water produced is 8.6778 grams.

Answer from: Quest

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6

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In the following balanced equation 2c2h6 + 7o2 --> 4co2 + 6h20 if 7.0 g of c2h6 react with 18g o...

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