If i initially have a gas at a pressure of 12 atm, volume of 23 liters, and temperature of 200 k, and then i raise the pressure to 14 atm and increase the temperature to 300 k, what is the new volume of the gas?

Answer : The volume of gas will be 29.6 L

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

where,

= initial pressure of gas = 12 atm

= final pressure of gas = 14 atm

= initial volume of gas = 23 L

= final volume of gas = ?

= initial temperature of gas = 200K

= final temperature of gas = 300K

Now put all the given values in the above equation, we get the final pressure of gas.

Therefore, the new volume of gas will be 29.6 L

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explanation:

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the answer is c. nacl