How many grams of zinc will be formed if 32.0 g of copper reacts with zinc nitrate? copper(i)nitrate is the other product.

We have to calculate amount of zinc formed in the given reaction.

The amount of zinc formed is 16.47 g.

The balanced chemical reaction between copper and zinc nitrate is as follows:

2Cu (s)  + Zn(NO₃)₂ (aq) → Zn (s) + 2CuNO₃ (aq)

From the reaction it is clear that one mole Zn is produced from two moles of Cu.

Atomic mass of copper is = 63.5 g and atomic mass of zinc is = 65.38 g.

As per reaction, 2 X 63.5 g= 127 g of copper produces 65.389 g of zinc. Therefore 32 g copper will produce  g = 16.47 g of zinc.

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :