6. gas a effuses 0.68 times as fast as gas b. if the molar mass of gas b is 17 g, what is the mass of gas a?
a) 29 g
b) 12 g
c) 7.8 g
d) 37 g

Option d) 37 g

Solution:

This question can be solved using the Graham's Law which states that:

Rate of effusion or diffusion of gas is indirectly proportional to the square root of its Molar Mass.

For two gases A and B, this formula can be written as:

= Rate of effusion of gas A

= Rate of effusion of gas B

= Molar mass of gas A

= Molar mass of gas B

We are given that, Gas A effuses 0.68 times as fast as Gas B. This means:

= 0.68 x

Using these values in the formula of Graham's law, we get:

Therefore, mass of gas A is 37 g, rounded to nearest unit.

the answer is definitely c.