What volume of carbon monoxide will contain 3.02x10^23 molecules?

11.23 L.

Explanation:

Using cross multiplication:

1.0 mole → 6.022 x 10²³ molecules.

??? mole → 3.02 x 10²³ molecules.

Using cross multiplication:

1.0 mole of CO occupies → 22.4 L.

0.5 mole of CO occupies → ??? L.

∴ The volume of CO contain 3.02 x 10²³ molecules = (22.4 L)(0.5 mole) / (1.0 mole) = 11.23 L.

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