100 points! also will mark brainlist if 100% correct and
the system ignited a tube of solid lithium perchlorate (liclo4) to make oxygen and lithium chloride (licl): liclo4 (s) > > 2o2 (g) + licl (s) if you have 500 g of liclo4, then how many liters of oxygen will the system make at the station’s standard operating conditions, a pressure of 101.5 kpa and a temperature of 294.15k? show all the steps involved in your work.

= 226 Liters of oxygen

We use the equation;

LiClO4 (s) → 2O2 (g) + LiCl, to get the moles of oxygen;

Moles of  LiClO4;

(500 g LiClO4) / (106.3916 g LiClO4/mol)

= 4.6996 moles

Moles of oxygen;

But, for every 1 mol LiClO4, two moles of O2 are produced;

= 9.3992 moles of Oxygen

V = nRT / P

= (9.3992 mol) x (8.3144621 L kPa/K mol) x (21 + 273) K / (101.5 kPa)

= 226 L of oxygen

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3