Ifyou spill a little of the benzoic acid you mix it with the lauric acid will the molecular weight that you calculate for the benzoic acid be too high or too low? why?

Hey there!:

A.Molecular weight of Benzoic acid will be same as expected

B.Molecular weight of Benzoic acid will be same as expected

Depression in freezing point is a colligative property and given by the equation :

ΔTf = Kf × m × i

where :

ΔTf is depression in freezing point of solvent after adding the solute.

Kf is freezing point depression constant for a particular solvent

m is molality (ie.moles of solute/Kg of solvent)

i is vant hoff factor(here lauric acid doesn't ionize hence i = 1)

Hope That helps!

i think it's c. i'm not sure but i think so.