Chemistry, 16.10.2019 11:30 angelinacortes11

Agas has a pressure of 0.40 atm at 55.0 °c. what is the pressure at standard temperature?
show the formula and which law is it? !

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Answers

Answer from: arianasg06

0.33 atm.

Explanation

By the Ideal Gas Law:

$P \cdot V = n \cdot R\cdot T$

Where

is the pressure of this gas,

is the volume of the ideal gas,

is the temperature of the gas in degrees Kelvins.

is the number of moles of gas particles in this gas, and

is the ideal gas constant.

$T_1 =55.0 \; \textdegree\text{C} = (55.0 + 273.15) = 328.15 \; \text{K}$ .

$T_2 = 0 \; \textdegree\text{C} = 273.15 \; \text{K}$ under STP standard conditions.

$P_1 = \dfrac{n \cdot R\cdot T_1}{V}$ ,

$P_2 = \dfrac{n \cdot R\cdot T_2}{V}$ .

The value of , , and shall be the same in the two equations.

Divide the second equation with the first:

$\dfrac{P_2}{P_1} = \dfrac{n\cdot R\cdot \dfrac{1}{V}}{n\cdot R\cdot \dfrac{1}{V}} \cdot \dfrac{T_2}{T_1} = \dfrac{T_2}{T_1}$ .

$P_2 = P_1 \cdot \dfrac{T_2}{T_1} = 0.40 \times \dfrac{273.15}{328.15} = 0.33 \; \text{atm}$ .

Answer from: Donlito8070

Gay-Lussac's Law; p₁/T₁ = p₂/T₂; 0.33 atm

Step-by-step explanation:

The volume and number of moles are constant, so we can use Gay-Lussac’s Law:

At constant volume, the pressure exerted by a gas is directly proportional to its temperature.

p₁/T₁ = p₂/T₂ Invert each side of the equation

T₁/p₁ = T₂/p₂ Multiply each side by p₂

T₂ = T₁ × p₁/p₂

p₂ = p₁ × T₂/T₁

Data:

p₁ = 0.40 atm; T₁ = 55.0 °C

p₂ = ?; T₂ = 0.0 °C

Calculations:

(a) Convert the temperatures to kelvins

T₁ = 55.0 + 273.15 = 328.15 K

T₂ = 0.0 + 273.15 = 273.15 K

(b) Calculate the new pressure

p₂ = 0.40 × 273.15/328.15

= 0.40 × 0.832

= 0.33 atm

The pressure drops to 0.33 atm.

Answer from: Quest

assuming that your periodic table has eighteen columns, you should highlight the four elements in the third column from the left of the table.

explanation

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the $3d$ have energy higher than those in the $4 s$ orbital while lower than those of the $4 p$ orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the $4s$ orbital is therefore filled right after $3p$ orbitals and before $3 d$ orbitals.

potassium has electron configuration $[\text{ar}] 4 s^{1}$ and calcium $[\text{ar}] 4 s^{2}$ . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration $[\text{ar}] 4 s^{2} \; 3d^{1}$ and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the $ns^{2} \; (n-1) p^{1}$ and should be highlighted as well.

Answer from: Quest

the answer is c.the valence of the atoms combine .

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