What would the final freezing point of water be if 3 mol of sugar were added to 1 kg of water (kf = 1.86c/(mol/kg) for water and i = 1 for sugar)?

is this for a test or are you genuinely interested? molality = mols sugar/kg solvent

Solve for molality

delta T = Kf*m

Solve for delta T and subtract from zero C to find the new freezing point.

or

-5.58

The final freezing point of water is -5.58

Explanation:

According to colligative properties of molecules,

where is the depression in freezing point of a solution, i is the vant hoff factor of solute, is the cryogenoscopic constant of solvent and m is molality of the solution.

Here solute is sugar and solvent is water.

Molality of solution = = = 3 mol/kg

So = -5.58

alkaline metals are lithium, sodium, rubidium, potassium, cesium and francium.

alkali metals have electronegativity from 0.7 to 1, lowest in periodic table of elements, which means that alkali metals (i group in periodic table) has positive oxidation number in compounds.

electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons,

for example, potassium is the alkali metal and has a single valence electron in the outer electron shell.

electron configuration of potassium is: ₁₉k 1s²2s²2p⁶3s²3p⁶4s¹.

they can not exist alone in nature, because they are very reactive.