[need answers with steps right away! ]
2.0g of ch4 (16.0) are added to 3.0g of o2 (32.0) at 400k and 950torr. what volume does this mixture occupy?

a 300 ml sample of gas was collected at stp weighs .90g. what is the molar mass of this gas?

1) 5.74 L.

2) 67.158 g/mol.

Explanation:

Q1:

PV = nRT

P is the pressure of the gases (P = 950 torr / 760 = 1.25 atm).

V is the volume of the gases (V = ??? L).

R is the general gas constant (R = 0.082 L.atm/mol.K).

T is the temperature of the gases (T = 400 K).

n is the no. of moles of the gases.

no. of moles of CH₄ = mass / molar mass = (2.0 g) / (16.0 g/mol) = 0.125 mol.

no. of moles of O₂ = mass / molar mass = (3.0 g) / (32.0 g/mol) = 0.09375 mol.

∴ n = no. of moles of CH₄ + no. of moles of O₂ = 0.125 mol + 0.09375 mol =  0.21875 mol.

∴ V = nRT/P = (0.21875 mol)(0.082 L.atm/mol.K)(400 K) / (1.25 atm) = 5.74 L.

Q2:

PV = (mass/molar mass)RT.

The molar mass = (mass)RT/PV.

The mass of the gas = 0.90 g.

R = 0.082 L.atm/mol.K.

T = 273 K at STP conditions.

P = 1.0 atm at STP conditions.

V = 300.0 mL = 0.30 L.

c)red bank

explanation:

red bank is a borough in monmouth county, new jersey, incorporated in 1908 and located on the navesink river, the area's original transportation route to the ocean and other ports.

the answer is 0.8m.

by: nicholas