Aballoon with a pressure of 1 atm has a volume of 2 liters. if you were to immerse the balloon into water where it experienced a pressure of 4 atm. what would the new volume of the balloon be?

1/2 liters
8 liters
2 liters
7 liters

½ L  

Step-by-step explanation:

The temperature and amount of gas are constant, so we can use Boyle’s Law.

p₁V₁ = p₂V₂    Divide each side by p₂

 V₂ = V₁ × p₁/p₂

Data:

p₁ =  1 atm; V₁ = 2 L

p₂ = 4 atm; V₂ = ?

Calculations:

V₂= 2 L × (1 atm/4 atm)

V₂= 2 L × ¼

V₂ = ½ L

i just learnt this recently but i need to look through my notes again