Chemistry, 03.02.2020 16:51 nina2323

An unknown gas effuses at a speed one quarter of that of helium. what is the molar mass of the unknown gas? it is either sulfur di oxide or sulfur tri oxide. which gas is it.

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Answer from: Charley9752

sulfur dioxide.

Explanation:

Thomas Graham found that, at a constant temperature and pressure the rates of effusion of various gases are inversely proportional to the square root of their masses.

Rate of effusion ∝ 1/√molar mass.

(Rate of effusion of He) / (Rate of effusion of unknown gas) = (√molar mass of unknown gas) / (√molar mass of He).

An unknown gas effuses at a speed one quarter of that of helium.

∵ Rate of effusion of unknown gas = 1/4 (Rate of effusion of He)

∴ (Rate of effusion of He) / (Rate of effusion of unknown gas) = 4.

Molar mass of He = 4.0 g/mol.

∵ (Rate of effusion of He) / (Rate of effusion of unknown gas) = (√molar mass of unknown gas) / (√molar mass of He).

∴ 4.0 = (√molar mass of unknown gas) / √4 = (√molar mass of unknown gas) / 2.

∴ (√molar mass of unknown gas) = 8.0.

By squaring the both sides:

∴ molar mass of unknown gas = 64.0 g/mol.

The molar mass of sulfur dioxide = 64.0 g/mol and the molar mass of sulfur trioxide = 80.0 g/mol.

So, the unknown gas is sulfur dioxide.

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