Given 1.00 gram of (nh4)2 co3, how many grams of this sample would be due to hydrogen?

0.0832 g.

Explanation:

n = mass / molar mass = (1.0 g) / (96.09 g/mol) = 0.01 mole.

Using cross multiplication:

1.0 mole of (NH₄)₂CO₃ contains → 6.022 x 10²³ molecules.

0.01 mole of (NH₄)₂CO₃ contains → ??? molecules.

∴ The no. of molecules of (NH₄)₂CO₃ in 1.0 g = (0.1 mole)(6.022 x 10²³ molecules) / (1.0 mole) = 6.267 x 10²¹ molecules.

∴ The no. of H atoms in 1.0 g of  (NH₄)₂CO₃ = (8 x 6.267 x 10²¹ molecules) = 5.013 x 10²² atoms.

∴ The grams of 5.013 x 10²² atoms of H = (5.013 x 10²² atoms)(1.0 g/mol)(1.0 mol) / (6.022 x 10²³ atoms) = 0.0832 g.

idk i’m struggling too

did anyone actually do this? like if anyone has submitted this i rly need .