**98 points**

given 1.00 gram of (nh4)2 co3, how many grams of this sample would be due to hydrogen?

OP already did it - CONGRATS!!

here are the steps 2 get the same ans:

(NH4)2 CO3 has 2x N, 8x H, 1x C and 3x O per molecule

so its molecular mass = 2x14 + 8x1 + 1x12 + 3x16

=28+8+12+48

=96g

of that 96g, 8x1=8g is due to Hydrogen

so by ratio n proportion, 1.00g will have 1x8/96 = 1/12g = 0.083g of H

ill try to . no promises tho.

explanation:

a saline water is fed to a reverse osmosis unit at flow rate o rotameter connected to reject (retentate) line reads 8 installed in reject and permeate line reads 15.2 milli siemens/cm and 300 micro siemens/com respectively.