The reaction of hcl with naoh is represented by the equation hcl( aq) + naoh( aq) ® nacl( aq) + h 2o( l) what volume of 0.631 m hcl is required to titrate 15.8 ml of 0.321 m naoh?

8.04 mL.

How many moles of NaOH?

Note the unit:

.

.

How many moles of HCl?

As seen in the equation, HCl and NaOH reacts at a 1:1 ratio.

.

How many mL of HCl?

.

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

answer; the numbers of valence electrons in the acetic acid molecule (ch3co2h) is 24;