How many molecules are there in 65 g of silver nitrate (agno3)?

a.

3.82 × 1023

b.

2.3046 × 1023

c.

2.3046 × 1024

d.

3.82 × 1024

e.

2.3046 × 1012

The correct answer is B,

The first step to solving this problem is to find the molar mass of AgN. From the periodic table this can be found to be 169.87g/mol. As a reminder, Avogadro's Number tells us that there are 6.022×1 molecules per mol.

Now you can set up dimensional analysis to solve the problem as follows:

≈ 2.304

calculate how many grams of ammonia can be produced from 4.21 grams of

n2 + 3h2 = 2nh3

my answer:

25.0g n2 x (1 mol/ 28.0gn2) x (2 mol nh3/ 1 mol n2) x (17.0g nh3/ 1 molnh3) = 30.36g n2

25.0g h2 x (1 mol h2/ 2.00g h2) x (2 mol nh3/ 3 mol h2) x (17.0g nh3/ 1 mol nh3) = 141.67g h2

lr = n2

b.

the accuracy of the data.