If 18 ml of methanol is used to make an aqueous solution that is 15% methanol by volume, how many ml of solution is produced?

120.0 mL.

Explanation:

We suppose that the initial W% of methanol is 100.0 %

∴ (W%V) before dilution = (W%V) after dilution.

W% before dilution = 100.0 %, V before dilution = 18.0 mL.

W% after dilution = 15.0 %, V after dilution = ??? mL.

∴ V after dilution = (W%V) before dilution/W% after dilution = (100.0 %)(18.0 mL)/(15.0%) = 120.0 mL.

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