Acertain quantity of a gas occupies 61.3 ml at 68°c. if the pressure remains constant, what would the volume of the gas be at 17°c? a. 52 mlb. 72 mlc. 32 mld. 92 ml

For this case we have that by definition:

Where,

Since the pressure, the number of moles and the universal constant do not change, then the equation is reduced to:

Rewriting we have:

Matching state 1 and state 2, we have:

Clearing the volume in state 2 we have:

Then, replacing values:

Rounding off we have:

The volume of the gas at 17 ° C would be:

Option A

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2

you need to have a picture of the atom that way we can answer it