Astanding wave is established on a string that is fixed at both ends. if the string is vibrating at its fundamental frequency, how is the length of the string related to the wavelength of the standing wave? a. the length of the sting is equal to one-quarter of a wavelength. b. the length of the string is equal to the wavelength. c. the length of the string is equal to twice the wavelength. d. the length of the string is equal to one-half of a wavelengthe. the length of the string is equal to four times the wavelength

Two nitro no2 groups are chemically bonded to a patch of surface. they can't move to another location on the surface, but they can rotate (see sketch at right). it turns out that the amount of rotational kinetic energy each no2 group can have is required to be a multiple of ε, where =ε×1.010−24 j. in other words, each no2 group could have ε of rotational kinetic energy, or 2ε, or 3ε, and so forth — but it cannot have just any old amount of rotational kinetic energy. suppose the total rotational kinetic energy in this system is initially known to be 32ε. then, some heat is removed from the system, and the total rotational kinetic energy falls to 18ε. calculate the change in entropy. round your answer to 3 significant digits, and be sure it has the correct unit symbol.

Find the mass, in grams, of 5.00*10^23 molecules of f2

How can nonpolar molecule contain polar covalent bonds