What volume would co2 in problem 1 occupy at stp? problem 1's answer was 1.1x10^3 grams in 1.5x10^25 molecules of co2

= 560 L

1 mole of a gas at STP occupies a volume of 22400 cm³

Theerefore; in this question we find the volume occupied by  1.1x10^3 grams of CO2

1 mole of CO2 = 22.4 L

but, 1 mole of CO2 = 44 g

thus; 44 g = 22.4 L

Hence; 1.1x10^3 grams will occupy

= ((1.1x10^3 grams)/44)× 22.4

water and alcohols have similar properties because water molecules contain hydroxyl groups that can form hydrogen bonds with other water molecules and with alcohol molecules, and likewise alcohol molecules can form hydrogen bonds with other alcohol molecules as well as with water.

idk what is it? is this a question that you know the answer or u dont