Some thermodynamic properties of ethanol are listed in the table. thermodynamic properties property value c (solid) 0.5 j/g °c c (liquid) 1.0 j/g °c c (gas) 2.0 j/g °c melting point −114 °c boiling point 78 °c how much heat is released when 40.0 g of ethanol cools from −120 °c to −136 °c? 640 j 580 j 320 j 290

Option C - 320J

Explanation

Since ethanol solid at −120 °C and is only cooling down (it won’t change states) . The amount of Thermodynamic properties values c is given in form of solid, liquid and gas. Amount of energy released is calculated below.  

Formula,

= change in temperature  x specific heat capacity for solid ethanol x 40

=> 0.5 x 16x 40 = 320J

Therefore, the 320J of heat is released when 40.0g of ethanol cools.

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.