Asample of neon effuses from a container in 77 seconds. the same amount of an unknown noble gas requires 157 seconds. identify the gas.

Argon

Explanation:

To find the amount of an unknown noble gas that requires 157 seconds fo effuse from a container from which a same amount of sample of neon effuses in 77 seconds, you must use Graham's Law of effusion.

Graham's law of effusion states the rate of effusion of a gas is inversely proportional to the square root of the masses of its particles. Mathematically, that is:

Since, the other conditions (amount of gas and container) are the same for both gases, the rates and the times are inversely proportional; this is:

MolarMass₂ = (157 s / 77 s) × MolarMass₁

Molar Mass₁ = 20.180 g/mol

∴ MolarMass₂ = (157 s / 77 s) × 20.180 g/mol = 41  g/mol

        It is argon. The molar mass of argon is 30.948 g/mol. So, argon (Ar) is the answer.

chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.

2b2t

explanation:

2b2t