A7.5 l cylinder contains 5 moles of gas at a temperature of 274°c. what is its pressure in kilopascals (kpa)?

Answer;

 = 3032.15 kPa

Explanation;

Using the equation;

PV = nRT , where P is the pressure,. V is the volume, n is the number of moles and T is the temperature and R is the gas constant, 0.08206 L. atm. mol−1.

Volume = 7.5 L, T = 274 +273 = 547 K, N = 5 moles

Therefore;

Pressure = nRT/V

               = (5 × 0.08206 × 547)/7.5 L

               = 29.925 atm

But; 1 atm = 101325 pascals

Hence; Pressure = 3032150.63 pascals

                            = 3032.15 kPa

               

Idid the calculation and i get 875,000,000 which can be written as 8.75 x 10^6?

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