A39 liter scuba tank contains 310 grams of oxygen gas (o2, molar mass = 32.0 g/mol) at 19°c. calculate the pressure in kilopascals (kpa).

602.95 kPa.

Explanation:

where, P is the pressure of the gas in atm.

V is the volume of the gas in L (V = 39.0 L).

n is the no. of moles of the gas in mol.

R is the general gas constant (R = 0.082 L.atm/mol.K).

T is the temperature of the gas in K (T = 19.0 °C + 273.15 = 292.15 K).

The volume of the gas = nRT/P.

P = ??? atm, V = 39.0 L, R = 0.082 L.atm/mol.K, n = mass/molar mass = (310.0 g)/(32.0 g/mol) = 9.6875 mo, T = 19.0 °C + 273.15 = 292.15 K.

∴ P = nRT/V = (9.6875 mol)(0.082 L.atm/mol.K)(292.15 K)/(39.0 L) = 5.95 atm.

101.325 kPa = 1.0 atm.

∴ P = 5.95 atm x (101.325 kPa / 1.0 atm) = 602.95 kPa.

"record the time to complete a chemical reaction" would most likely be part of a lab procedure.