What is the oxidation state of mn in mn3o4

The oxidation state of manganese(mn) in the given compound is +3.

The given compound;

Mn₃O₄

The oxidation state of the given compound is determined as shown below;

the oxidation number of oxygen (O) is -2

let the oxidation number of manganese (Mn) = x

3(x) + 4(-2) = 0

3x - 8 = 0

3x = 8

Thus, the oxidation state of manganese (mn) in the given compound is +3.

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Mn*3+O*4

3x + (-2)4=0

Next by solving for X,

X=8/3=2.6

There is something wrong with the question I guess, please check

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