Hat is the % of each element in the compound mg3(po4)2?

1. First calculate the total molar mass of the entire compound.

Mg = 3 x 24.31 = 72.93 g/mol

P = 2 x 30.97 = 61.94 g/mol

O = 8 x 16.00 = 128.00 g/mol

* Add them up;

72.93 + 61.94 + 128.00 = 262.87 g/mol

2. Take the individual masses of each element that you calculated, divide them by the total mass (262.87 g/mol) and then multiply by 100.

Mg = 72.93/262.87 = 0.2774 x 100 = 27.74%

P = 61.94/262.87 = 0.2356 x 100 = 23.56%

O = 128.00/262.87 = .4870 x 100 = 48.70%

3. All of the percentages should add up to equal 100%.

* Hope this helps

2b2t

explanation:

2b2t

it is stable as it is in group 0 which have full outer shells of electrons