How many grams of nano3 are required to saturate 200 grams of water at 10 degrees celsius

162.0 g.

Explanation:

The solubility of NaNO₃ in 100.0 g of water at 10.0°C is 81.0 g/ 100 g water.

Using cross multiplication:

81.0 g of NaNO₃ form saturated solution at 10.0°C in → 100.0 g of water.

g of NaNO₃ form saturated solution at 10.0°C in → 200.0 g of water.

∴ The grams of NaNO₃ form saturated solution at 10.0°C in 200.0 g of water = (81.0 g)(200.0 g)/(100.0 g) = 162.0 g.

the child will have heterozygous dominant chromosomes as characters of his father are dominant over the characters of his mother.

the child is heterozygous

answer

i think the answer is a) as air pressure in an area increases, the density of the gas particles in that area decreases.

hope it